Page 49 - Maths Class 06
P. 49

EX AM PLE 2.  The floor of a hall is 15.5 m and 10.5 m. Square-shaped tiles are to be fixed on it. Find the
                          larg est size of tile and also find the num ber of tiles re quired to cover the floor of the hall
                          com pletely.

            SO LU TION :  The larg est size of tile will be the HCF of 15.5 m and 10.5 m.
                          We know that,
                                         15.5 m = 1550 cm                                  2     1550      2     1050

                          and            10.5 m = 1050 cm                                  5     775       3     525
                          We shall find the HCF of 1550 and 1050.                          5     155       5     175

                          Now,           1550 =  2 5 5 31´ ´ ´
                                                                                           31    31        5     35
                                                 b
                                                                                                 1         7     7
                          and            1050 =  2 3 5 5 7´ ´ ´ ´
                                                                                                                 1
                          \    The HCF of 1550 and 1050 is 2 5 5´ ´ , i e. . 50.
                          Thus, the largest size of the tile is 50 cm.
                                                                             )
                          Now, Area of the floor of the hall =(1500 1050  sq. cm
                                                                      ´
                                                     )
                          Area of one tile =(50 50  sq. cm
                                                 ´
                                                            1550  ´1050
                          \     Number of tiles required =                = 31 21 651
                                                                               ´
                                                                                   =
                                                               50  ´50
                          Also, recall  that LCM  of two or more numbers is the     smallest number which is exactly
                          divisible by each of the given numbers.
            EX AM PLE 3.  Find the least (small est) num ber which is ex actly di vis i ble by 8, 10 and 12.
            SO LU TION :  The re quired num ber is LCM of 8, 10 and 12.

                          Now,                    8 =  2 2 2´ ´
                                                10 =  2 5´
                                                12 =  2 2 3´ ´

                          \  LCM = ´ ´ ´ ´ =2 2 2 3 5  120
                          Thus, the required number is 120.

            EX AM PLE 4.  Find the least 3-digit num ber which when di vided by 18, 24 and 32 leaves a re main der 7 in
                          each case.
            SO LU TION :  The re quired num ber is 7 added to the LCM of 18, 24 and 32.
                          Now,                  18 =  2 3 3´ ´

                                                24 =  2 2 2 3´ ´ ´
                                                32 =  2 2 2 2 2´ ´ ´ ´
                          \  LCM = ´ ´ ´ ´ ´ ´ =2 2 2 2 2 3 3  288

                          Hence, the required number is 288 7+     =  295.
            EX AM PLE 5.  In a morn ing walk, three friends step off to gether. Their steps mea sure 80 cm, 85 cm and
                          90 cm re spec tively. What is the min i mum (least) dis tance each should cover so that all can
                          cover the same dis tance in com plete steps?


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